PP Presentation
Specific Heat Capacity - an example
If 25.0 g of Al cool from 310 oC to 37 oC, how many joules of heat energy are lost by the Al?
where DT = Tfinal - Tinitial = 37 - 310 = -273 K
q = (0.902 J/g•K)(25.0 g)(-273 K)
q = -6160 J
negative sign of q ® heat is “lost by” or transferred from Al